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If an object is placed 1 m (3 ft) away from a light source and the lux level is 3200 lux, what is the lux level at a distance of 8 m (24 ft)?
Answer : A
If an object is placed 1 meter (3 feet) away from a light source with a lux level of 3200 lux, the lux level decreases according to the inverse square law of light. At a distance of 8 meters (24 feet), the lux level can be calculated as:
NewLuxLevel=3200lux(8/1)2=3200lux64=50lux\text{New Lux Level} = \frac{3200 \text{ lux}}{(8/1)^2} = \frac{3200 \text{ lux}}{64} = 50 \text{ lux}NewLuxLevel=(8/1)23200lux=643200lux=50lux
Thus, at 8 meters, the light intensity drops significantly to 50 lux.
Which camera model provides the greatest deterrence effect?
Answer : A
The AXIS P3247-LVE provides the greatest deterrence effect. This model is a robust, vandal-resistant network camera designed for outdoor use with advanced features such as IR illumination, advanced video analytics, and a rugged design. Its visible presence and high-quality image capture capabilities serve as a strong deterrent to potential intruders and vandals.
Attackers may try to deceive system owners into installing altered firmware which may include malicious code. Axis helps prevent this by using
Answer : A
Axis helps prevent attackers from deceiving system owners into installing altered firmware by using signed firmware. Signed firmware ensures that only authentic and unaltered firmware can be installed on the device. This process involves cryptographic signatures that verify the integrity and authenticity of the firmware, thus preventing malicious code from being introduced into the system.
Two cameras are streaming 6 Mbit/s each. Approximately how much storage is required to record one hour of video from both streams?
Answer : B
To calculate the storage required to record one hour of video from two cameras streaming at 6 Mbit/s each, we use the following steps:
1.Total bitrate for both cameras: 6Mbit/s2=12Mbit/s6 \text{ Mbit/s} \times 2 = 12 \text{ Mbit/s}6Mbit/s2=12Mbit/s
1.Convert Mbit/s to Mbyte/s: 12Mbit/s8=1.5Mbyte/s12 \text{ Mbit/s} \div 8 = 1.5 \text{ Mbyte/s}12Mbit/s8=1.5Mbyte/s
1.Calculate the total data for one hour: 1.5Mbyte/s3600seconds=5400Mbytes1.5 \text{ Mbyte/s} \times 3600 \text{ seconds} = 5400 \text{ Mbytes}1.5Mbyte/s3600seconds=5400Mbytes
1.Convert Mbytes to Gbytes: 5400Mbytes1024=5.27Gbytes5400 \text{ Mbytes} \div 1024 = 5.27 \text{ Gbytes}5400Mbytes1024=5.27Gbytes
Approximately, the storage required is 5.4 GB.
What is the maximum power level at the powered device for PoE class 2?
Answer : A
The maximum power level at the powered device for PoE class 2 is 6.49 W. Power over Ethernet (PoE) class 2 devices are designed to consume between 3.84 W and 6.49 W. This classification helps ensure that network devices receive the appropriate power levels required for their operation.
